All categories

3 years ago

HELP Which of the lines below has a slope of 0?

Mathematics

1 answer:

Juliette [100K]3 years ago

4 0

Answer:

C has a zero slope

Step-by-step explanation:

A horizontal line has a slope of zero

A vertical line has an undefined slope

A positive slope goes up from left to right

A negative slope goes down from left to right

You might be interested in

Match each graph with the correct equation written in<br> standard form. Explain your reasoning.

My name is Ann [436]

The graphs and their equations are:

Line 1: 6x - 2y = -10
Line 2: 9x - 9y = -45
Line 3: 3x - 12y = -60

<h3>How to determine the equations of the graphs</h3>

The three lines are linear equations, because they are all straight lines.

Also, the lines have the same y-intercept (this is so, because they cross the y-axis at the same point), but they have the same slope

Next, we rewrite the equations in slope-intercept form.

So, we have:

$3x - 12y = -60$

Divide through by -12

$-0.25x +y = 5$

Make y the subject

$y = 0.25x + 5$

$6x - 2y = -10$

Divide through by 2

$3x - y = -5$

Make y the subject

$y = 3x + 5$

$9x - 9y = -45$

Divide through by -9

$-x + y = 5$

Make y the subject

$y = x + 5$

Line 1 has the highest slope, while line 3 has the least slope.

So, we have the following equations:

Line 1: 6x - 2y = -10
Line 2: 9x - 9y = -45
Line 3: 3x - 12y = -60

Read more about linear equations at:

brainly.com/question/14323743

5 0

2 years ago

ABCD is a trapezoid. Point E is the midpoint of AD and point F is the midpoint of B.

VikaD [51]

2 cm. because you would subtract 5 and 3.

6 0

3 years ago

Find the value of 1<br> and 1/10-1/5

Andreyy89

9514 1404 393

Answer:

9/10

Step-by-step explanation:

(1 1/10) - 1/5 = (1 1/10) -2/10 = 1 + (1/10 -2/10) = 1 -1/10 = 9/10

1.1 -0.2 = 0.9 = 9/10

5 0

3 years ago

What is the volume of the figure?

FromTheMoon [43]

It’s going to be the area of the triangle on the side times the length, so 0.5 x 36 x 15 x 48 = 12960

7 0

3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago