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disa [49]
3 years ago
8

Graphic characters used to identify items on an unordered list first line indent is called _______

Computers and Technology
1 answer:
Elodia [21]3 years ago
4 0

Answer: they are calles BULLETS

Explanation:

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Given three floating-point numbers x, y, and z, output x to the power of z, x to the power of (y to the power of z), the absolut
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Solution :

x = float_(input())

y = float_(input())

z = float_(input())

res1 = x**z

res2 = x**(y**z)

res3 = abs(x-y)

res4 = (x**z)**0.5

print('{:.2f} {:.2f} {:.2f} {:.2f}'.format(res1,res2,res3,res4))

Output is :

5.0

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6 0
2 years ago
The angles of a quadrilateral are in the ratio 1:2:3:4 what is the largest angle​
zheka24 [161]

Answer:

144°

Explanation:

The sum of the measures of interior angles of a quadrilateral is 360°

The ratio of angle measures is 1:2:3:4

Total ratio = 1+2+3+4=10

The angles will be :

1/10 * 360°= 36°

2/10*360°=72°

3/10*360°=108°

4/10*360°=144°

The largest angle is 144°

7 0
3 years ago
The faster alcohol is consumed, the faster it reaches the __________.
Anni [7]
The faster it reaches the bloodstream

6 0
3 years ago
Read 2 more answers
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

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So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

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= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
a key part of staying safe is employing good habits. drag the step number to the proper sequence triple a
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where are the step number. I can't find any

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