The oracle11g server stores information about objects in the database, including information about constraints in the tables. <span>An </span>Oracle database is a set of files that store Oracle data in persistent disk storage.<span>A database </span>instance<span> is a set of memory structures that manage database files</span>.
Answer:
Se explaination
Explanation:
/Declaring variables
integer currentPrice
integer lastMonthPrice
integer changeLastMonth
float mortagage
//Reading input
currentPrice = Get next input
lastMonthPrice = Get next input
//Calculating price change
changeLastMonth = currentPrice - lastMonthPrice
//Calculating mortagage
mortagage = (currentPrice * 0.051) / 12
//Printing output
Put "This house is $" to output
Put currentPrice to output
Put "\nThe change is $" to output
Put changeLastMonth to output
Put " since last month." to output
Put "\nThe estimated monthly mortgage is $" to output
Put mortagage to output
Answer:
There is also an attachment below
Explanation:
Since we are talking about binary search, let's assume that the items are sorted according to some criteria.
Time complexity of binary search is O(logN) in worst case, best case and average case as well. That means it can search for an item in Log N time where N is size of the input. Here problem talks about the item not getting found. So, this is a worst case scenario. Even in this case, binary search runs in O(logN) time.
N = 700000000.
So, number of comparisions can be log(N) = 29.3 = 29.
So, in the worst case it does comparisions 29 times
If you have 10 bits available then you can interpret any number in range
.
The system therefore could represent the actual temperature of 39°C.
Hope this helps.
Answer:
Please find the complete solution in the attached file.
Explanation: