Carbohydrate residues attached to the membrane lipids are always positioned on the extracellular side of the membrane
Carbohydrates are significant parts of the cell membrane, present just on the external surface of the plasma layer, and are appended to proteins, framing glycoproteins, or lipids, and framing glycolipids. These carbohydrate chains might comprise 2-60 monosaccharide units and can be either straight or branched.
The carbohydrates of the membrane are engaged with cell bond and acknowledgment and go about as a physical barrier. Enormous, uncharged particles, for example, glucose can't diffuse through the membrane.
These carbohydrates structure particular cell markers, that permit cells to perceive one another. These markers are vital in the resistant framework, permitting safe cells to separate between body cells, which they shouldn't assault, and unfamiliar cells or tissues, which they ought to.
Learn more about membrane lipids here,
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I think it’s all of the above because they can all be found in the air and in water sources
Butterflies taste with their feet to tell on which plans they lay their eggs on. Plus, they have a taste sensors on their feet. Hope I helped you. xoxo :)
The area is called the anterior fontanel and closes anytime between 9 and 18 months of age.
Answer:
-1.9mL/min
Explanation:
The rate of O₂ production can be calculated by the formula
= ( Final volume - initial volume)/time(min).
From the graph provided and attached below, the rate of O₂ production or rate of photosynthesis at light intensity of 8 is about 3.75 mL/min.
The rate of O₂ production is taken as the rate of photosynthesis. It is expected to progressively increase from light intensity 0 as light intensity increases. However, at very high light intensity, the rate slows down as water becomes limiting and the stomata closes in order to conserve water.
Question in order
Experiment 2: Respiration in the Dark
Calculate the volume change for respiration in the dark. As you already saw from earlier questions,
oxygen production is fairly constant. You will not need to calculate the individual volume changes.
Just subtract the original volume at 00:00:00 from the final reading at 00:02:00. Record your answer
for use in a later question.
<em>Note: depending on when you started the timer there is a range of possible answers. Pick the answer that is closest to this</em>
What was the volume change for respiration in the dark?
Correct answer:
-1.9 mL/min