Answer:
The equilibrium partial pressure of NO2 is 0.152 atm
Explanation:
Step 1: Data given
Initial pressure of NO2 = 0.500 Atm
Total pressure inside the vessel at equilibrium = 0.674 atm
Step 2: The balanced equation
2 NO2(g) ⇌ 2 NO(g) + O2(g)
Step 3: The initial pressures
pNO2 = 0.500 atm
pNO = 0 atm
pO2 = 0 atm
Step 4: The pressure at the equilibrium
pNO2 = 0.500 - 2x
pNO = 2x
pO2 = x
Total pressure = 0.674 = (0.500 - 2x) + 2x + x
0.674 = 0.500 + x
x = 0.174
pNO2 = 0.500 - 2*0.174 = 0.152 atm
pNO = 2x = 0.348 atm
pO2 = x = 0.176 atm
The equilibrium partial pressure of NO2 is 0.152 atm
Your answer is D. Hope this helps!
