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3 years ago

Reflection obtained from a smooth surface is called a

Chemistry

1 answer:

Snowcat [4.5K]3 years ago

4 0

The answer is A.regular reflection

Hope this helps.

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Neutral atoms of a specific element can have different numbers of which of the following?

Anit [1.1K]

Neutrons for example isotopes

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3 years ago

What is the wavelength (in meters) of an electromagnetic wave whose frequency is 2.63 × 1012 s−1?

aleksklad [387]

To find the wavelength of an electromagnetic wave for the given frequency can be determined by using the formulaSpeed=Wavelength x FrequencyWavelength=Speed/FrequencyGenerally Speed of the electromagnetic wave is 3x10^8 m/sBy substituting the values Wavelength=3x10^8 m/s / 2.63x10^12 s^-1Wavelength=1.14 x 10^-4 metres

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3 years ago

What are the main concepts that make up the study of earth science?

Rashid [163]

The structure and history of Earth and what forces formed it. The investigation of earth in the context of the solar system and universe

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3 years ago

A sample of glucose (C6H1206) contains 0.75 moles of oxygen. How many moles of hydrogen does this sample contain?

Snowcat [4.5K]

Answer:

$15molH$

Explanation:

Hello,

In this case, given that one mole of glucose, contains six moles of oxygen (subscript), we can also see it contains twelve moles of hydrogen (subscript), therefore, the moles of hydrogen in the sample are computed by:

$0.75molO*\frac{1molC_6H_{12}O_6}{6molO}*\frac{12molH}{1molC_6H_{12}O_6}\\ \\=1.5molH$

Best regards.

6 0

3 years ago

Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: PCl5(g) → PCl3(g) + Cl2(g)

nalin [4]

Answer:

The value of $\Delta H$ for the desired reaction will be 249.75 KJ.

Explanation:

The desired reaction is shown below

$\textrm{PCl}_{5}\left ( g \right )\rightarrow \textrm{PCl}_{3}\left ( g \right )+\textrm{Cl}_{2}\left ( g \right )$

The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.

$P_{4}\left ( s \right )+6Cl_{2}\left ( g \right )\rightarrow 4PCl_{3}\left ( g \right ) \\4PCl_{5}\left ( g \right )\rightarrow P_{4}\left ( s \right )+10Cl_{2}\left ( g \right )$

Net Enthalpy change for the desired reaction

$\displaystyle \frac{3438-2439}{4} \textrm{ KJ} = 249.75 \textrm{ KJ}$

$\Delta H = 249.75 \textrm{ KJ}$

6 0

4 years ago