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satela [25.4K]
4 years ago
10

Race times at the local monthly 5k run are normally distributed, with a mean time of 32 minutes and a standard deviation of 4 mi

nutes. Using the empirical rule, approximately what percent of racers cross the finish line between 28 and 36 minutes? 32% 68% 95% 99.7%
Mathematics
1 answer:
galina1969 [7]4 years ago
7 0

Answer:

68%

Step-by-step explanation:

The mean is 32 minutes, and the standard deviation is 4 minutes.

28 is 1 standard deviation below the mean, and 36 is 1 standard deviation above the mean.

According to the empirical rule, 68% of a normal distribution is between -1 and 1 standard deviations.  95% is between -2 and 2 standard deviations.  99.5% is between -3 and 3 standard deviations.

So the answer is 68%.

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Determine which numbers are solutions for x&gt;7 from the solution set<br> of { 7,8,9}
Vitek1552 [10]

Answer:

8, 9

Step-by-step explanation:

Since x > 7

This means that x cannot equal 7 but must be greater values than 7.

Thus 8 and 9 are solutions

8 0
3 years ago
Two consecutive even intergers whose sum is 110
Harrizon [31]
Consecutive even integers are 2 apart
they are
x and x+2


sum is 110
x+x+2=110
2x+2=110
minsu 2 both sides
2x=108
divide both sidedse by 2
x=54
x+2=56
the numbers are 54 and 56
7 0
3 years ago
-3x − 5 = 16<br> What would x = ?
kari74 [83]

Answer:

Step-by-step explanation:

-3x=16+5

-3x=21

x=21/-3

x= -7

7 0
3 years ago
Domain and range of graph need ASAP
Lostsunrise [7]

Answer:

Domain: -6 \leq x \leq 3

Range: -3 \leq x \leq 6

Step-by-step explanation:

The domain is the set of real values which can be inputted into a function and produce a real output. In this case, the domain is the following: -6 \leq x \leq 3, because this is the set of real values for which the function will produce a real output.

The range is the set of real values which a function outputs when a value from the domain is entered into the function. This is the set of y-values that one can see on the graph, the possible y-values are in between (-3) and (6).

6 0
2 years ago
The scatter plot shows a correlation between the years and the rainfall in centimeters in Tennessee.
nataly862011 [7]

Answer:

7

4

Step-by-step explanation:

The <u>actual values</u> are shown on the given graph as <u>blue points</u>.

The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.

From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43).  It appears that the regression line is at y = 50 when x is the year 2000.

⇒ Difference = 50 - 43 = 7 cm

<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.

From inspection of the graph, in the year 2003 the actual rainfall was 44 cm,  shown by point (2003, 40).  It appears that the regression line is at y = 40 when x is the year 2003.

⇒ Difference = 44 - 40 = 4 cm

<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>

3 0
2 years ago
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