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satela [25.4K]
3 years ago
10

Race times at the local monthly 5k run are normally distributed, with a mean time of 32 minutes and a standard deviation of 4 mi

nutes. Using the empirical rule, approximately what percent of racers cross the finish line between 28 and 36 minutes? 32% 68% 95% 99.7%
Mathematics
1 answer:
galina1969 [7]3 years ago
7 0

Answer:

68%

Step-by-step explanation:

The mean is 32 minutes, and the standard deviation is 4 minutes.

28 is 1 standard deviation below the mean, and 36 is 1 standard deviation above the mean.

According to the empirical rule, 68% of a normal distribution is between -1 and 1 standard deviations.  95% is between -2 and 2 standard deviations.  99.5% is between -3 and 3 standard deviations.

So the answer is 68%.

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mixas84 [53]
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2 years ago
solve the average time for a student to complete this quiz is 24 24 minutes with a standard deviation of 2 minutes. What is the
LuckyWell [14K]

Answer:

The correct answer is "(18, 30) minutes".

Step-by-step explanation:

Mean,

= 24

Standard deviation,

= 2

The range of minutes where 99.7% of individuals completed the quiz will be:

= Mean \pm 3\times Stdev

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= 24 \pm 3\times 2

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now,

= 24-6

= 18

Or,

= 24+6

= 30

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3 0
3 years ago
Dani’s estimate for the cost of tiling her bathroom is $50 plus $3 per square foot. She says that she can model the cost with a
jarptica [38.1K]
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4 0
3 years ago
From experience, an airline knows that only 80% of the passengers booked for a certain flight actually show up. If 9 passengers
Olenka [21]

Answer:  0.74

Step-by-step explanation:

Given : The probability that the passengers booked for a certain flight actually show up : p=0.80

The number of passengers are randomly selected : n= 9

Binomial probability formula to find the probability of getting success in x trial :-

P(x)=^nC_xp^x(1-p)^{n-x}

Then , the probability that more than 6 of them show up will be :-

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Hence, the probability that more than 6 of them show up = 0.74

7 0
3 years ago
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