Answer:
So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.
Absorbance is the inverse of transmittance so,
A = 1/T
Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:
A ∝ b · c
As Transmittance, 
% Transmittance, 
Absorbance,
Hence, 
is the algebraic relation between absorbance and transmittance.
Trinomial 2x² + 4x + 4.
It's of the form ax²+bx+c and it's discriminant is Δ=b² - 4.a.c
(in our case Δ = 4² - (4)(2)(4) → Δ = - 32
We know that: x' = -1 + i and x" = -1 - i
If Δ > 0 we have 2 rational solutions x' and x"
If Δ = 0 we have1 rational solution x' = x"
If Δ < 0 we have 2 complex solutions x' and x", that are conjugate
In our example we have Δ = - 16 then <0 so we have 2 complex solutions
That are x'= [-b+√Δ]/2.a and x" = [-b-√Δ]/2.a
x' =
Answer:
-5/0= undefined
Step-by-step explanation:
m = y2- y1 / x2- x1
m = -3-2/ 17-17
m= -5/0
3x+4y=12
4y=12-3x
y=(12-3x)/4 <---------- This is f(x)
---------------------
3x+4y=12
3x=12-4y
x=(12-4y)/3
Therefore:
f⁻¹(x)=(12-4x)/3
=[4(3-x)]/3
We will assume that each of their cups holds exactly 1 cup of liquid. Let <em>m</em> represent milk and <em>c</em> represent coffee.
Jane = 1/2<em>m</em> + 1/2<em>c</em> to represent 1/2 milk and 1/2 coffee
Jean, June, and Joan = 3(1/4<em>m</em> + 3/4<em>c</em>) [they all 3 like the same ratio, so multiply the expression by 3], to represent 1/4 milk and 3/4 coffee
Ian = 1<em>c </em>(since he likes black coffee, his entire 1-cup dish of coffee will be coffee)
Adding these together we have:
1/2<em>m</em> + 1/2<em>c</em> + 3(1/4<em>m</em> + 3/4<em>c</em>) + 1<em>c</em>
= 1/2<em>m</em> + 1/2<em>c</em> + 3/4<em>m</em> + 9/4<em>c</em> + 1<em>c</em>
Find a common denominator:
= 2/4<em>m</em> + 2/4<em>c</em> + 3/4<em>m</em> + 9/4<em>c</em> + 1<em>c</em>
Convert the 1 whole to a fraction:
= 2/4<em>m</em> + 2/4<em>c</em> + 3/4<em /><em>m</em> + 9/4<em>c</em> + 4/4<em>c</em>
Combine your <em>m</em>'s:
= 5/4<em>m</em> + 2/4<em>c</em> + 9/4<em>c</em> + 4/4<em>c</em>
Combine your <em>c</em>'s:
= 5/4<em>m</em> + 15/4<em>c</em>
We know there is 4 times as much coffee as milk. Looking at the two fractions we have left, we can see that 15/4<em /> = 3(5/4). We would expect to see 4(5/4), since there is 4 times as much coffee. That means we have 5/4 or 1 1/4 of the liquid left.
