If you trying to answer what would be on all the sides if it were to be equal then 51 would be the answer if it's not what the question seems I will try and answer, but be more explanatory.
Volume of cylinder = πr²h
Volume = π (12)² × 17
= 2448 π units³
Thus the answer is (d)
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
3) f(x) = 3(x + 2)^2 - 1.
Step-by-step explanation:
f(x) = 3x² + 12x +11
f(x) = 3(x^2 + 4x) + 11 Completing the square:
f(x) = 3[(x + 2)^2 - 4] + 11
f(x) = 3(x + 2)^2 -+3*-4 + 11
f(x) = 3(x + 2)^2 - 12 + 11
f(x) = 3(x + 2)^2 - 1.
Answer:
20% probability
Step-by-step explanation:
First, we need to calculate the area of all the figures inside the rectangle.
Area of triangle= 1/2 BH
So, 3x2=(6)
Area of Square= L^2
3x3=(9)
Area of rectangle= LxW
=60.
60+9+6= 75.
75 is the total area.
Now, lets find the added area of only the triangle and square.
9+6= 15
The probability will be 15/75=
Convert into percent form
= 20%
Hope this helps and please mark me brainliest :)
