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Afina-wow [57]
2 years ago
12

(a) How could you calculate 23 x 4 on your calculator if the 4 button is broken? (b) How could you calculate 23 x 21 if the 2 bu

tton on your calculator is broken?
Mathematics
1 answer:
Crank2 years ago
3 0

Answer:

23 x 4

=> 23 x (2 + 2)

=> 23 x 2 + 23 x 2

23 x 21

=> 23 x (3 x 7)

=> (23 x 3) x (23 x 7)

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(y^-5)^-10y^10<br><br>the answers are in the image​
fredd [130]

Answer:

\large\boxed{y^{60}}

Step-by-step explanation:

(y^{-5})^{-10}y^{10}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=y^{(-5)(-10)}y^{10}=y^{50}y^{10}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=y^{50+10}=y^{60}

6 0
3 years ago
Simplify:<br> (2-2x5-5)-4
Pavlova-9 [17]

Answer:

(2*5^2)+4/3^2-5

(2*25)+4/3^2-5

50+4/3^2-5

50+1.7-5

46.7

7 0
2 years ago
4X + 5Y = 21<br> -4X + 8Y = -8<br> And<br> X + 5Y = 5<br> 3X - 5Y = 3
sergij07 [2.7K]

Answer:

for the first one

Step-by-step explanation:

(x,y)=(4,1)

6 0
3 years ago
What is 96 ÷ 16 + (25x2) -15-3?
marysya [2.9K]
96/16+ (25*2) -15 -3
= 6+ 50 -15 -3
= 56 -15 -3
= 41 -3
= 38

The final answer is 38~
3 0
3 years ago
Solve each equation<br>1) v- 10=-9​
Luba_88 [7]

Answer:

v=1

Step-by-step explanation:

v-10=-9\\\\    +10    +10\\\\v=1

6 0
3 years ago
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