Answer:
5 and 11
Step-by-step explanation:
Make equations:
x+y = 16
3x-4 = y
Substitute 3x-4 as y in x+y = 16
You get x + 3x - 4 = 16
Simplify into 4x - 4 = 16
Add 4 on both sides
you get 4x = 20
Divide each side by 4,
You get x = 5. Plug 5 back into x+y = 16
Subtract 5 from both sides, and you get y = 11
First you need to get a common denominator. The first two problems already have a common denominator, so you just have to find the sum and difference of the two problems, respectively.
6.) (9y-3)/(y^2-5)
8.) 3/xy^3
Two find a common denominator, find the smallest value that has BOTH denominators as factors.
10.) 8x^3*y^3 is the common denominator
Answer: 2/(8*x^3*y^3)
12.) Factor x^2 + 4x + 4 to get (x+2)(x+2)
Therefore, x+2 is already part of x^2 + 4x + 4
(x+4)/(x^2+4x+4)
14.) Factor both denominators..
4(y+2) and y(y+2)
So the common denominator would be 4y(y+2)
The first fraction is missing a "y" so multiply the numerator by y to get y^2
The second fraction is missing a "4" so multiply the numerator by 4 to get 4
(y^2 - 4)/(4y(y+2))
So can factor the numerator to get (y+2)(y-2). There if a (y+2) on top and bottom so they cancel out.
Answer: (y-2)/4y
Answer:
Seems to be some missing numbers in the question
Step-by-step explanation:
There are two dog runs at the pet store. The first one is ??? feet long and the second one is ??? feet long. The owner of the store wants to increase the length of the first one by ??? feet. She wants to increase the length of the second one by ??? feet. (a) After the lengths of the dog runs are increased, what is the length of the longer dog run? Explain how you found your answer.
