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kakasveta [241]
3 years ago
7

The LCM of 12 and 6 is 6. True or False

Mathematics
2 answers:
elena-s [515]3 years ago
7 0

Answer:

false but Least common multiple (LCM) of 6 and 12 is 12.

Lostsunrise [7]3 years ago
5 0

Answer: False

Step-by-step explanation:

Step 1: Find the prime factor of 6

Which are 6 = 2 × 3

Step 2: Find the prime factor of 12

Which are 12 = 2 × 2 × 3

Multiply each factor the greater number of times it occurs in steps 1 and 2

LCM = 2 × 2 × 3

LCM = 12

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A cube is cut in to three parts by vertical slices find the volume of the shaded area The length and width of original is 20 cm
Anni [7]

Answer:

4000 cm^3

Step-by-step explanation:

Note that no image was attached for reference purposes

Step one:

We are given that the original length and width of the cube is 20cm

if the cut part is 10cm

hence the dimension of the cut part is

lenght = 20cm

Width= 20cm

Hieght= 10cm

Step two:

the volume of the cut part will be

Volume= 20*20*10

Volume= 4000 cm^3

7 0
3 years ago
What’s 1/8 of 3200 and how u find it
deff fn [24]

Answer: here u go

Step-by-step explanation:

6 0
2 years ago
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Find the amount in an account where $500 is invested at 2.5% compounded continuously for period of 10 years
Alex17521 [72]

Hi

500 *1.025^10 ≈ 640.04

4 0
3 years ago
Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
Ugo [173]

Answer:

Side\ B = 6.0

\alpha = 56.3

\theta = 93.7

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with \alpha, \beta, \theta

[See Attachment for Triangle]

A = 10cm

C = 12cm

\beta = 30

What the question is to calculate the third length (Side B) and the other 2 angles (\alpha\ and\ \theta)

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

B^2 = A^2 + C^2 - 2ABCos\beta

Substitute: A = 10,  C =12; \beta = 30

B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30

B^2 = 100 + 144 - 240*0.86602540378

B^2 = 100 + 144 - 207.846096907

B^2 = 36.153903093

Take Square root of both sides

\sqrt{B^2} = \sqrt{36.153903093}

B = \sqrt{36.153903093}

B = 6.0128115797

B = 6.0 <em>(Approximated)</em>

Calculating Angle \alpha

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute: A = 10,  C =12; B = 6

10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 180 - 144 *Cos\alpha

Subtract 180 from both sides

100 - 180 = 180 - 180 - 144 *Cos\alpha

-80 = - 144 *Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}

\frac{-80}{-144} = Cos\alpha

0.5555556 = Cos\alpha

Take arccos of both sides

Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)

Cos^{-1}(0.5555556) = \alpha

56.25098078 = \alpha

\alpha = 56.3 <em>(Approximated)</em>

Calculating \theta

Sum of angles in a triangle = 180

Hence;

\alpha + \beta + \theta = 180

30 + 56.3 + \theta = 180

86.3 + \theta = 180

Make \theta the subject of formula

\theta = 180 - 86.3

\theta = 93.7

5 0
3 years ago
-4x -7 - 3x + 4 = 25
zimovet [89]

Answer:

x=-4

Step-by-step explanation:

-4x -7 - 3x + 4 = 25

-7x=25-4+7

x=-28/7

x=-4

7 0
3 years ago
Read 2 more answers
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