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s2008m [1.1K]
3 years ago
9

Pablo used paper cone cups with a diameter of 3 inches and a height of 4 inches p. His supply store stopped carrying these paper

cones. So he had to start using standard paper cups with a diameter of 3 inches and a height of 4 inches
Mathematics
2 answers:
Alika [10]3 years ago
7 0
Im pretty sure it is  24 is the answer
elena55 [62]3 years ago
6 0
The answer will be 24
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Sarah kicked a ball in the air. The function
Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

b=-5  

c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

6 0
3 years ago
FOR EASY BRAINLIEST ANSWER AND EXPLAIN!! ASAP
Alina [70]
Answer: 9 1/3 minutes
First create an equation with the given information; with x being the commercial time, 30=3x+2, now solve for x. First subtract 2 from each side and get 28=3x and then divide each side by 3 to get 9 and 1/3 minutes.
3 0
2 years ago
Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn
ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0
3 years ago
Which property is illustrated by the statement? 8⋅x=x⋅8
weeeeeb [17]

Answer:

Any value of x makes the equation true.

Step-by-step explanation:

all real numbers

interval notation:(-infinity, infinity)

pls mark as brainliest lol

4 0
2 years ago
(b-2)² + 10 for b = 7​
elixir [45]

whatttttttt? i have no idea what that is

7 0
3 years ago
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