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4 years ago

9

Pablo used paper cone cups with a diameter of 3 inches and a height of 4 inches p. His supply store stopped carrying these paper

cones. So he had to start using standard paper cups with a diameter of 3 inches and a height of 4 inches

2 answers:

Alika [10]4 years ago

7 0

Im pretty sure it is 24 is the answer

elena55 [62]4 years ago

6 0

The answer will be 24

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boyakko [2]

Answer:

boom bam ba boom bam ba

4 0

2 years ago

Radioactive isotopes are commonly used to estimate artifact ages. Let X be the time in years for a Carbon-14 atom to decay to Ni

Alexeev081 [22]

Answer:

a) 1 / years

b) P ( 5000 < X < 6000) = 0.06222

c) 8267 years

d) T_1/2 = 5730.25 years

Step-by-step explanation:

Given:

- The decay constant λ = 1 / 8267

- X is an exponential random Variable

Find:

a. What are the units of What are the units of λ?

b. What is the probability the decay time is between 5000 and 6000 years?

c. Compute SD(X).

d. Compute the median decay time. The result is called the half-life of Carbon-14?

Solution:

- The decay constant λ means the rate at which the C-14 atoms decays into N-14 atom. The rate is expressed in units of 1 / year.

- The random variable X follows an exponential distribution which has a probability mass function and cumulative density functions as follows:

P ( X = t ) = λ*e^(-λ*t)

P ( X = t ) = e^(-t/8267) / 8267

P ( X < t ) = 1 - e^(-λ*t) = 1 - e^(-t/8267)

- The probability of the decay time between years 5000 and 6000 years is:

P ( 5000 < X < 6000) = 1 - e^(-6000/8267) - 1 + e^(-5000/8267)

P ( 5000 < X < 6000) = 0.06222

- The standard deviation of the exponential distribution is given by:

SD(X) = 1 / λ = 8267 years

- The median decay time for an exponential distribution is given by:

T_1/2 = Ln(2) / λ = Ln(2)*8267

T_1/2 = 5730.25 years

3 0

4 years ago

Read 2 more answers

6 (d-4) = 18d <br><br> someone please help :(

Pie

Answer:

d = -2

Step-by-step explanation:

6 (d-4) = 18d

6d - 24 = 18 d

-24 = 18d - 6d

-24 = 12d

d = -24 / 12

d = -2

6 0

4 years ago

Read 2 more answers

Which statements must be true?

slamgirl [31]

Answer:

The options 2,3 and 5 are correct.

Step-by-step explanation:

From the figure it is noticed that the points U,V and W are midpoint of JK,KL and JL respectively.

Midpoints theorem of triangle states that the line connecting the midpoints of two sides is parallel to third side and its length is half of the third side.

The points U and W are midpoint of JK and JL. Using midpoint theorem, we get

$UW=\frac{1}{2}KL$

$UW\parallel KL$

The points U and V are midpoint of JK and KL. Using midpoint theorem, we get

$UV=\frac{1}{2}JL$

$UV\parallel JL$

The points V and W are midpoint of KL and JL. Using midpoint theorem, we get

$VW=\frac{1}{2}JK$

$2VW=JK$

$VW\parallel JK$

Therefore options 2, 3 and 5 are correct.

7 0

4 years ago

Giovanni justifies whether the expression -4x-8 is equivalent to -2(x+1)-2(x+3) by letting x=3 in both expressions. What is the

Lorico [155]

Answer:

The value of each expression when x=3 will be -20 and -20.

Step-by-step explanation:

Given the expression

-4x-8

setting x=3

= -4(3)-8

=-12-8

=-20

Given the expression

-2(x+1)-2(x+3)

setting x=3

=-2(3+1)-2(3+3)

=-2(4)-2(6)

=-8-12

=-20

so we conclude that the value of both the expressions was -20 when we substituted the value x=3.

Therefore, the value of each expression when x=3 will be -20 and -20.

3 0

3 years ago