Answer:
well you didn't show problem 11 but here is a pretty photo of Port orford Oregon
We have to calculate the probability of picking a 4 and then a 5 without replacement.
We can express this as the product of the probabilities of two events:
• The probability of picking a 4
,
• The probability of picking a 5, given that a 4 has been retired from the deck.
We have one card in the deck out of fouor cards that is a "4".
Then, the probability of picking a "4" will be:

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

We then calculate the probabilities of this two events happening in sequence as:

Answer: 1/12
Hey! I'll provide you the answers!
First you want to simplify the equation using cross-multiplication.

Finally, you would want to divide both sides by 15.
n = 161
there are 4 tens in a deck so probability of picking a ten is 4/52 reduced to 1/13
there are 13 clubs in a deck, probability for that is 13/52 reduced to 1/4
probability for both is 1/13 x 1/4 = 1/52
The answer is..........
A. 9