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djyliett [7]
3 years ago
9

Please help me with this math problem Evaluate C/2 - 3 + 6/D when c=14 and d=3

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
8 0

I hope this helps you!

lbvjy [14]3 years ago
7 0

\frac{c}{2}  - 3 +  \frac{6}{d }  =  \\  =  \frac{14}{2}  - 3 +  \frac{6}{3}  =  \\  = 7 - 3 + 2 =  \\ =  6
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I need help with this please....Thanks
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Answer:

The total cost of redecoration is £66, that is less than £75. Tenant can decorate the room for the budget set.

Step-by-step explanation:

Lets start calculating the areas of shorter and longer walls.

The area of shorter wall is

2.65m*2.98m=7.897m^2.

The area of longer wall is

3.94m*2,65m=10.441m^2.

Together the area of one long and one short wall is

7.897m^2+10.441m^2=18.338m^2.

The area to be painted ( one short and one long wall) is 18.338m^2 that is less than 30m^2, and hence only one tin of paint is needed (costs £16).

If there is assumed that the sheets of wallpaper must be whole from floor to ceiling, the calculations are following.

We get from one roll

10m/2.65m=3.77 sheets; we can use only 3 of them

The width of the walls is 3,94m+2,98m=6,92m,

and division gives 6.92m/0.52m=13,3... .

Hence it requires 14 sheets, that is 5 rolls of wallpaper.

Wallpaper costs 5*£10=£50 and altogether it is needed £50+£16=£66 to redecorate the room.

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