Two high school basketball teams have identical records of 15 wins and 2 losses.

A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat

Nesterboy [21]

Complete Question

A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat.

Write and solve an equation to find the weights of the cat and the dog.

Answer:

Weight of cat = x = 12 pounds

Weight of Dog = y = 34 pounds

Step-by-step explanation:

Let's represent:

Weight of cat = x

Weight of Dog = y

A dog weighs 2 pounds less than 3 times the weight of a cat.

y = 3x - 2........ Equation 1

The dog weighs twenty two more pounds than the cat

y = x + 22....... Equation 2

The equation is given as:

y = y

3x - 2 = x + 22

Collect like terms

3x - x = 22 + 2

2x = 24

x = 24/2

x = 12 pounds

Solving for y using any of the equations:

y = 3x - 2

y = 3 × 12 - 2

y = 36 - 2

y = 34 pounds

Therefore:

Weight of cat = x = 12 pounds

Weight of Dog = y = 34 pounds

6 0

3 years ago

a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou

Fed [463]

Answer:

$\displaystyle P(A)=\frac{6}{11}$

Step-by-step explanation:

Probabilities

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

$\Omega=\{WW,WN,NW,NN\}$

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

$A=\{WN,NW\}$

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

$\displaystyle \frac{5}{11}$

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

$\displaystyle \frac{6}{10}$

Thus the option WN has the probability

$\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}$

Now for the second option NW. The initial probability to pick a non-white counter is

$\displaystyle \frac{6}{11}$

The probability to pick a white counter is

$\displaystyle \frac{5}{10}$

Thus the option NW has the probability

$\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}$

The total probability of event A is the sum of both

$\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}$

$\boxed{\displaystyle P(A)=\frac{6}{11}}$

7 0

3 years ago

How does recipe conversion factors work? For example, if I have a soup that is originally 24 servings and has 16 oz of fish, and

Neporo4naja [7]

You have to find the unit rate, which in this case means the amount of fish you need per serving of soup.

If 16 oz of fish makes 24 servings, then 16/24 oz = 2/3 oz makes 1 serving.

Now multiply both quantities by 10, so that 10 servings require 20/3 oz ≈ 6.67 oz of fish.

A more direct way to do this is to solve for x in the following equation:

(16 oz fish) / (24 servings) = (x oz fish) / (10 servings)

Then (omitting units)

x = 10 • 16 / 24 = 20/3

7 0

3 years ago

Use zero property to solve the equation. F(x)=3x(x+7)-2(x+7)

oksian1 [2.3K]

Answer:

x = -7 or x = 2/3

Step-by-step explanation:

I'm assuming you meant solve for x when f(x) = 0.

f(x) = 3x(x + 7) - 2(x + 7)

0 = (x + 7)(3x - 2) -- Both terms have a common factor of (x + 7) so we can group them

x + 7 = 0 or 3x - 2 = 0 -- Use ZPP

x = -7 or x = 2/3 -- Solve

7 0

3 years ago

The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area

miv72 [106K]

Answer:

20 square feet

Step-by-step explanation:

The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area

Step 1

We find the Length and Width of the deck

Perimeter of a rectangle = 2L + 2W

The length of a rectangular deck is five times it's width

W = Width

L = Length = 5W

P = 24 feet

Perimeter = 2(5W) + 2W

24 = 10W + 2W

24 = 12 W

W = 24/12

W = 2 feet

Solving for L

L = 5W

L = 5 × 2 feet

L = 10 feet

Step 2

We find the area of the deck

Area of the deck(Rectangle) = Length × Width

= 10 feet × 2 feet

= 20 square feet

4 0

2 years ago