Answer:
28 hours
Step-by-step explanation:
let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.
Given,
In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.
Now, according to the question,
after 'x' hours,
⇒ 80° - 1.5°(x) = 94° - 2°(x)
⇒ 0.5°(x) = 14°
⇒ x = 28
Hence, Till 28 more hours the temperature in Mesquite Texas be greater than that in Brownsville.
Miles earned= ((1÷8)×11)÷1
= 1.375 miles
average speed=total distance/total time
=1.375÷3.5=0.3928 miles/min
Am pretty sure you should add 2 to both of the numbers than multiple I THINK.
Answer:
Let the speed of the train be x km/h.
Case 1:
Distance = 288 km
Speed = x km/h
Time = Distance/Speed
= 288/x h
Case 2:
Distance = 288 km
Speed = (x+4) km/h
Time = 288/x + 4 h
Since 288/x > 288/x + 4
288/x - 288/x+4 = 1
288[1/x - 1/x+4 ] = 1
[ x + 4 - x / x(x + 4) ] = 1/288
[4 / x^2 + 4x ] = 1/288
x^2 + 4x = 1152
x^2 + 4x - 1152 = 0
x^2 + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0 , x - 32 = 0
x = -36 , x = 32
x = -36 , rejected since speed cannot be negative.
Therefore , speed of the train = 32 km/h
