Hi there, (6z²+z-1)(9z-5)=(6z²+z+-1)(9z+-5)=(6z²)(9z)+(6z²)(-5)+(z)(9z)+(z)(-5)+(-1)(9z)+(-1)(-5)=54z³-30z²+9z²-5z-9z+5=54z³-21z²-14z+5. Therefore, the answer is 54z³-21z²-14z+5.

8 0

3 years ago

10x + 5x – 3 = 2(2x – 1)

DiKsa [7]

Answer:

The answer is x = 1/11

Step-by-step explanation:

hope this helps

10x + 5x – 3 = 2(2x – 1)

10x+5x-3=4x-2

15x-4x=-2+3

11x=1

To find x divide both sides by 11

11x/11=1/11

x= 1/11

8 0

3 years ago

Read 2 more answers

Rewrite the equation below so that it does not have fractions.

bearhunter [10]

Answer:

$60+10x=6$

Step-by-step explanation:

Hi there!

$4+\displaystyle \frac{2}{3} x=\frac{2}{5}$

To get rid of the fraction $\displaystyle \frac{2}{3}$ , multiply both sides of the equation by 3 (the denominator):

$3(4+\displaystyle \frac{2}{3} x)=3(\frac{2}{5})\\\\3*4+\frac{3*2}{3}x =\frac{3*2}{5} \\\\12+2x =\frac{6}{5}$

To get rid of the fraction $\displaystyle \frac{6}{5}$ , multiply both sides of the equation by 5 (the denominator):

$\displaystyle 5(12+2x) =5(\frac{6}{5})\\\\5*12+5*2x=\frac{5*6}{5} \\\\60+10x=6$

I hope this helps!

8 0

2 years ago

Read 2 more answers

The functions f and g are defined by f(x)=2x+1 and g(x)= 5x-1. finda. fg(3)​

The functions f and g are defined by f(x)=2x+1 and g(x)= 5x-1. finda. fg(3)