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3 years ago

5

Find the distance between the points (a, 0) and (0, b). StartRoot (a minus b) squared EndRoot StartRoot a squared + b squared En

dRoot StartRoot (a + b) squared EndRoot StartRoot a squared minus b squared EndRoot

2 answers:

borishaifa [10]3 years ago

5 0

Answer:

square root of (a^ + b^) or the option b

Step-by-step explanation:

its right on edge 2020

hope this helped :)

Daniel [21]3 years ago

4 0

Option number b

is ur answer

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If the maker of the promissory note fails to pay the note on the due date,the note is said to be

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When the maker of a promissory note fails to pay, the note is said to be <u>dishonored.</u>

Step-by-step explanation:

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3 years ago

What is the radius of a sphere with a volume of 4.5π cubic centimeters?

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V=(4/3)pir^3
4.5pi=(4/3)pir^3
divide both sides by pi
4.5=(4/3)r^3
times 3/4 both sides
3.375=r^3
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2 years ago

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The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

so

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

so

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago

Can someone plz correct me plz

S_A_V [24]

The answer is D. You’d need to minus the area of the circle away from the area of the triangle to get the area of the shaded region

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2 years ago

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What is the diamiter of 37.68

Sphinxa [80]

Answer:

The diameter is 12

Step-by-step explanation:

37.68/3.14 = D π/ 3.14

D = 12 The diameter equals twelve.

7 0

3 years ago