Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030
1 answer:
F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20
f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200
Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)
8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
= 20 + 1/40
= 20.025
You might be interested in
She would pay 15 dollars for the dress because it would be 75 percent off.
Las razones de los lados de un triángulo rectángulo se llaman razones trigonométricas.
Espero te ayude :)
Answer:
Step-by-step explanation:
(x+2)(3x-3)
= 3x^2 -3x + 6x - 6
= 3x^2 + 3x - 6
3(4k+1) is the result I hope it helps you
Answer:
320/50=6.4
Step-by-step explanation:
Distance + time would give you your SPEED
So you would divide it not multiply
Brainliest plz