Using derivatives, it is found that:
i)
ii) 9 m/s.
iii)
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:
item i:
Velocity is the <u>derivative of the position</u>, hence:
Item ii:
The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:
Item iv:
The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:
Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer: IXL
Step-by-step explanation:
9514 1404 393
Answer:
(2/3)(e^t +1)^(3/2)
Step-by-step explanation:
Use the substitution ...
u = e^t +1
Then du = e^t and you are finding the integral of ...
∫u^(1/2)·du
which you know by the power rule is ...
(2/3)u^(3/2) = (2/3)(e^t +1)^(3/2)
Answer:
10.5
Step-by-step explanation: