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Sholpan [36]
3 years ago
6

Which statements below are true? Select all that apply.

Mathematics
1 answer:
kotegsom [21]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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fence is to be built to enclose a rectangular area of 250 square feet. The fence along three sides is to be made of material tha
Morgarella [4.7K]

Answer:

23.05 x 10.85

Step-by-step explanation:

Area of Rectangular Fence = L * W = 250ft^{2}

L * W = 250

W = \frac{250}{L}                                      ................................... (i)

Perimeter = 2L + 2W

Three sides cost 4 dollars per foot = 4(2L) + 4W

(The two lengths must be constructed with the 4 dollars materials)

Fourth side costs 13 dollars per foot = 13W

Cost = 4(2L) + 4W + 13W

C = 8L + 17W                         ...................................... (ii)

Substitute (i) into (ii)

C = 8L + 17 (\frac{250}{L})

C = 8L + \frac{4250}{L}  

Plotting this equation with L on the x-axis and cost on the y-axis

minimum cost will be when L ≈ 23.05 ft

W = \frac{250}{23.05} ≈ 10.85 ft

minimum cost = 8(23.05) + \frac{4250}{23.05}

minimum cost = 184.4 + 184.382

minimum cost ≈ 368.78 dollars

5 0
4 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
T(d) is a function that relates the number of tickets sold for a movie to the number of days since the movie was
Flauer [41]

Answer: The same number of tickets was sold on the fourth day and tenth day.

Step-by-step explanation:

Given, T(d) is a function that relates the number of tickets sold for a movie to the number of days since the movie was  released.

The average rate of change in a function with respect to the independent variable gives the value of change in a particular period.

If average rate of change in T(d) for the interval d = 4 and d = 10 is  is 0 , that means nothing has been changed in the number of tickets sold on 4th day and 10th day after the film release.

Hence, the correct statement is "The same number of tickets was sold on the fourth day and tenth day."

8 0
3 years ago
Read 2 more answers
Please help solve this problem
Yuri [45]

Answer: OPTION C

Step-by-step explanation:

By definition you know that:

\sqrt[n]{a^n}=a

and by the exponents properties you also know that:

a^n*a^m=a^{(n+m)}

Now, descompose 18 into its prime factors:

18=2*3*3=2*3²

Rewrite the expression and simplify (Keep on mind that: \sqrt{x^4}=x^{(\frac{4}{2})}=x^{2}). Then, you obtain:

\sqrt{2*3^2*x^4*y*y^2}=3x^2y\sqrt{2y}

7 0
3 years ago
Read 2 more answers
Triangle ABC and triangle CDE are similar right triangles. Which proportion can be used to show that the slope of AC is equal to
shusha [124]

Answer:

Option C is the correct option.

Step-by-step explanation:

Considering the triangle ABC, the slope of the line CA is given by \frac{AB}{BC} = \frac{6 - 3}{-3 - (- 1)}

Again, considering the triangle CDE, the slope of the line EC is given by

\frac{CD}{DE} = \frac{3 - (- 3)}{- 1 - 3 }

Since CA and EC represents the same straight line so, we can write

\frac{6 - 3}{-3 - (- 1)} = \frac{3 - (- 3)}{- 1 - 3 }

Therefore, option C is the correct option. (Answer)

8 0
4 years ago
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