There are 36 possible ways of throwing two dices. The following lists are shown in ordered pair: (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
a) a pair of 3's The probability is 1/36 because there is only one pair which is (3,3). b) any pair The probability is 6/36 or 1/6 because the number of pairs are (1,1) (2,2) (3,3) (4,4) (5,5) and (6,6). c) at least one 4 The probability is 10/36 or 5/18 because there would be (4,1) (4,2) (4,3) (4,5) (4,6) (1,4) (2,4) (3,4) (5,4) (6,4) for any combination. d) a total of 9 The probability is 4/26 or 2/13 because (4,5) (5,4) (3,6) (6,3) are the totals of 9. 5) a total greater than 8 The probability is 10/36 or 5/18. Just find the ordered pair having a sum greater than 8.
you have to concentrate at the 1 because because it's at the tens place, if the 1 is not greater than 5 you don't have to do anything. you just have to remove the two numbers before the the number 6and you so it automatically should be 624600.
To round a number to the nearest hundredth , look at the next place value to the right (the tens this time). Same deal: If it's 4 or less, just remove all the digits to the right. If it's 5 or greater, add 1 to the digit in the hundredths place, and then remove all the digits to the right.
