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Andru [333]
2 years ago
5

Simplify and solve this equation for q: 3q + 5 + 2q – 5 = 65.

Mathematics
2 answers:
svlad2 [7]2 years ago
6 0
Add like terms:
5q = 65
divide by 5:
q = 13
so, B. is the answer
Flauer [41]2 years ago
4 0
3(23)+5+2(23)-5=? 69+5+46-5=? 74+46-5=? 120-5=? 115 A is not the answer 3(13)+5+2(13)-5=? 39+5+26-5=? 44+26-5=? 70-5=? 65 B is the answer
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A game involves drawing a single card from a standard deck. One receives 60 cents for an ace, 30 cents for a king, and 5 cents f
professor190 [17]

Answer:

The expected game value is -1 cent

Step-by-step explanation:

Here, we want to calculate the expected value of the game

We have 4 aces and 4 kings, including 26 red cards

The number of aces is 4

Probability of drawing an ace is 4/52 = 1/13

Probability of drawing a king is also 4/52 = 1/13

There are 26 red cards

The number of red cards that are neither ace nor king

There are 2 red aces and 2 red kings

So the number of cards that are red but are not

aces nor kings are 26-2-2 = 22

The probability of selecting this is 22/52 = 11/26

So the expected value is simply the probability multiplied by the amount

Thus, we have;

(60 * 1/13) + (30 * 1/13) + (5 * 11/26)

= 60/13 + 30/13 + 55/26

= (120 + 60 + 55)/26 = 9.038 cents which is approximately 9 cents

we subtract this from the 10 cents we are playing with, thus we are left with 9-10 = -1 cent

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2 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer and Step-by-step explanation:

C(x) be the statement "x has a cat"

D(x) be the statement "x has a dog"

F(x) be the statement "x has a ferret".

Universe = x = all students in your class.

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b) All students in your class have a cat, a dog, or a ferret  =  ∀x(C(x) ∨ D(x) ∨ F(x))

c) Some students in your class has a cat and a ferret but not a dog  = ∃x (C(x) ∧ F(x) ∧ ¬D(x))

d) No student in this class has a cat, a dog and a ferret  ¬∃x (C(x) ∧ D(x) ∧ F(x))

e) For each of the three animals, cats, dogs and ferrets, there is as student in your class who has one of the three animals.  (∃xC(x)) ∧ (∃xD(x)) ∧ (∃xF(x))

4 0
3 years ago
(2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)
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Answer:

2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)

Step-by-step explanation:

2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)

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