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Temka [501]
3 years ago
14

What is the rational exponent expression of 3 square root 4n

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\sqrt[4n]{3^2}\implies 3^{\frac{2}{4n}}\implies 3^{\frac{1}{n}}
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If 35 gms of pure drug are contained in 150 mls, how many grams are contained in 75 mls?
Leviafan [203]

Answer:

17.5

Step-by-step explanation:

The ratio of "pure drug" to liquid is 35:150

Therefore to evaluate for 75 mls we get the ratio 75/2150 or simply 1/2

we can then multiply 35 by the ratio 1/2

35/2=17.5

State the answer

In 75 mls there are 17.5 grams of pure drug

8 0
3 years ago
The bread is on sale for $1.50 so Erica is also going to buy candy or gum. Which can she afford?
Alborosie
Ok, so she started off with $5.00. 


She bought milk for $2.99.

She buys bread, which costs $1.50. 

Subtracting the money she wasted, the total would be $0.51. 

The only thing she could buy is 5 pieces of gum for 25 cents. 

Her change will be $0.26. 

Hope this helps!
6 0
3 years ago
How do you do this problem?
zhenek [66]

Answer:

A) g is increasing, and the graph of g is concave up.

Step-by-step explanation:

g'(x) = ∫₀ˣ e^(-t³) dt

Since e^(-t³) is always positive, ∫₀ˣ e^(-t³) dt is positive when x > 0.  So the function is increasing.

Find g"(x) by taking the derivative using second fundamental theorem of calculus:

g"(x) = e^(-x³)

g"(x) is always positive, so the function is always concave up.

5 0
3 years ago
The perimiter of each face of a rubiks cube is 22.2 centimeters. What is the length of and edge of the rubiks cube?
ivanzaharov [21]

Answer:

3.7 cm

Step-by-step explanation:

22.2 / 6 = 2.7

Hope that helps!

5 0
3 years ago
Two digit-
igor_vitrenko [27]

Let the number = 10x+y

x+y = 9

y-x = 1

(x+y)+(y-x) = 9+1

2y = 10

y = 10/2

<h3><u>y = 5</u></h3>

x+y = 9

9-y = x

x = 9 - 5

<h3><u>x = 4</u></h3>

<h2>So, your number is <u>45</u></h2>

... Hope this will help...

4 0
3 years ago
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