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Strike441 [17]
3 years ago
11

a dragonfly can beat its wings 30 times per seconed.write an equation in slope intercept from that shows the relationship betwee

n flying time in secons and the number of times the dragonfly beats its wings
Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

Answer:

s=30f

Step-by-step explanation:

S = second; F = flying time.

Since it can flap its wings 30 times, each second, we have already found our answer. The relationship between flying time (Wing flaps) and seconds is 30. In other words, it beats it's wings 30 times each second. Which is what the question asks.

Now we just have to write the equation:

s=30f

This is because the seconds are <u>dependent</u> on the flap of wings, so s would be the y value.

Hope it Helps!

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What are the coordinates of point B on \overline{AC} such that AB = 1/2 BC
marta [7]

Answer:

C. B(x,y) = \left(3,-\frac{16}{3} \right)

Step-by-step explanation:

Let A(x,y) = (6,-7), B(x,y) = (x,y) and C(x,y) = (-3,-2). From statement we know that AB = \frac{1}{2}\cdot BC, which is equivalent to the following linear algebraic formula:

B(x,y) -A(x,y) = \frac{1}{2}\cdot [C(x,y)-B(x,y)] (1)

B(x,y)-A(x,y) = \frac{1}{2}\cdot C(x,y)-\frac{1}{2}\cdot B(x,y)

\frac{3}{2}\cdot B(x,y) = \frac{1}{2}\cdot C(x,y)+A(x,y)

B(x,y) = \frac{1}{3}\cdot C(x,y) +\frac{2}{3}\cdot A(x,y) (2)

Then, the coordinates of point B on AC are:

B(x,y) = \frac{1}{3}\cdot (-3,-2)+\frac{2}{3}\cdot (6,-7)

B(x,y) = \left(-1, -\frac{2}{3}\right)+\left(4, -\frac{14}{3} \right)

B(x,y) = \left(3,-\frac{16}{3} \right)

Which means that correct answer is C.

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Step-by-step explanation:

Ans. - 17

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