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balandron [24]
3 years ago
13

What is 40.15% of 23?

Mathematics
2 answers:
Lilit [14]3 years ago
8 0
1\%=\frac{1}{100}\\\\ 40.15\%\cdot 23=40.15 \cdot \frac{1}{100}\cdot 23=\frac{923.45}{100}=9.2345
klemol [59]3 years ago
6 0

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~

This is actually a pretty easy question... all we have to do is 23 * 0.4015

We know that %40.15 = 0.4015, because 40.15/100 = 0.4015...

So 23 * 0.4015 = 9.2345

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A shopper paid $2.52 for 4.5 pounds of potatoes,$7.75 for 2.5 pounds of broccoli,and $2.45 for 2.5 pounds of pears.What is the u
Sidana [21]

Answer:

Step-by-step explanation:

A shopper paid $2.52 for 4.5 pounds of potatoes. This means that the unit price for each potato would be

2.52/4.5 = 0.55556

Approximately $0.6 per pound.

The shopper paid $7.75 for 2.5 pounds of broccoli. This means that the unit price for each broccoli would be

7.75/2.5 = $3.1 per pound.

The shopper paid $2.45 for 2.5 pounds of pears. This means that the unit price for each pear would be

2.45/2.5 = $0.98 per pound

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the area of the shape is 8cm

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Bob left work and traveled to school at an average speed of 25 mph. If it took bob 35 minutes to reach school, how far is Bob's
S_A_V [24]
In order t solve this problem, let's first convert 35 minutes into hours. If we divide 35/60 then we will have an answer of 0.58. So 35 minutes is equal to 0.58 hours. After that, we multiply 0.58 to 25. We will do this in order to get the total miles that was traveled in 35 minutes from Bob's school to his work. So the final answer to that question will be 14.58. So the answer is Bob's school is 14.58 miles away from his place of work. 
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Damon is 12 3 4 years old. Dwight is 1 1 2 years younger than Damon and Jane is 1 1 5 years younger than Dwight. How old is Jane
lana [24]

Damon's age =\tt 12 \frac{3}{4}

Dwight's age :

= \tt1 \frac{1}{2}  \: years \: younger \: than \:  \: Damon

= \tt12 \frac{3}{4}  - 1 \frac{1}{2}

=\tt  \frac{51}{4}  -  \frac{3}{2}

▪︎LCM of 4 and 2 = 4

=\tt  \frac{51}{4}  -  \frac{3 \times 2}{2 \times 2}

=\tt  \frac{51}{4}  -  \frac{6}{4}

= \tt \frac{45}{4}

\color{plum} = \color{plum}\tt11 \frac{1}{4}

Thus, Dwight is \color{plum}\tt11 \frac{1}{4} years old.

Jane's age :

=\tt  1\frac{1}{5}  \: years \: younger \: than \: Dwight

=  \tt11\frac{1}{4} - 1 \frac{1}{5}

=\tt  \frac{45}{4}  -  \frac{6}{5}

▪︎LCM of 4 and 5 = 20

=  \tt\frac{45 \times 5}{4 \times 5}  -  \frac{6 \times 4}{5 \times 4}

=\tt  \frac{225}{20}  -  \frac{24}{20}

= \tt \frac{201}{20}

\color{plum} =\color{plum} \tt10 \frac{1}{20}

Thus, Jane is \tt10 \frac{1}{20} years old.

Therefore, Jane's age = \color{plum} \tt10 \frac{1}{20}

4 0
3 years ago
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