Answer:
Step-by-step explanation:
Given quadratic equation is,
y = -2x² + 4x + 5
y = -2(x² - 2x) + 5
y = -2(x² - 2x + 1 - 1) + 5
y = -2(x² - 2x + 1) + 2 + 5
y = -2(x - 1)² + 7
This equation is in the vertex form of the quadratic equation,
y = a(x - h)² + k
where, (h, k) is the vertex of the parabola.
Therefore, vertex of the given quadratic equation is (1, 7)
The equation can be rewritten as y = -2(x - 1)² + 7.
Therefore, the vertex of the graph of the function y = -2x² + 4x + 5 in the xy-coordinate plane is located at the point (1, 7).
The range of a function are the dependent variables for which the function exists. The range of the function will be y ≥ 5
<h3>Range of a function</h3>
The range of a function are the dependent variables for which the function exists
Given the function below;
f(x) = √x+7 + 5
The function can only exist for values less than or equal to -7 that is x ≤ -7.
Substitute
f(-7) = √-7+7 + 5
f(-7) = 5
The range of the function will be y ≥ 5
Learn more on range here: brainly.com/question/2264373
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Answer:
y = –|x - 1| + 3
Step-by-step explanation:
The "vertex" is (1 , 3)
y = –|x - 1| + 3
Answer:
1
Step-by-step explanation:
Hope This helps! : )
