Answer:
a) 
b) 
If we compare the p value and the significance level given we see that 
we have enough evidence to reject the null hypothesis at 5% of significance.
Step-by-step explanation:
Data given and notation
n=114 represent the random sample taken
estimated proportion of people that their approval rating might have changed
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Hypothesis
We need to conduct a hypothesis in order to test the claim that true proportion of people that their approval rating might have changed is 0.58 or no.:
Null hypothesis:
Alternative hypothesis:
Part a
(1)
Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
Part b: Statistical decision
The significance level provided . The next step would be calculate the p value for this test.
Since is a bilateral test the p value would be:
If we compare the p value and the significance level given we see that we have enough evidence to reject the null hypothesis at 5% of significance.
Answer:
A is correct.
x>5 means all numbers greater than BUT not equal to 5.
The open circle means "not equal".
So, A is correct.
Hope this helps!
Answer:
W = 16 in
Step-by-step explanation:
P = 2L + 2W
56 = 2(12) + 2W
56 = 24 + 2W
56-24 = 2W
32 = 2W
W = 32/2
W = 16 in
Best regards
Answer:
There is no common difference
Step-by-step explanation:
4 9 13 18
diff 5 4 5
Because the difference between 9 and 13 is 4
and the difference in the other terms is 5
there is no common differeence
Answer:
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The proportion of infants with birth weights between 125 oz and 140 oz is
This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So
X = 140
has a pvalue of 0.9772
X = 125
has a pvalue of 0.8413
0.9772 - 0.8413 = 0.1359
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
