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Elodia [21]
3 years ago
9

A 52-foot guy-wire is attached to a power pole to provide support. The wire is attached to the pole 36 feet above the ground and

to an anchor on the ground. How far from the base of the pole is the anchor?

Mathematics
2 answers:
Luda [366]3 years ago
4 0
Check the picture below.

Cerrena [4.2K]3 years ago
3 0

<em>Answer:</em>

The anchor is 4√201

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2 years ago
Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the
iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are \frac{10\sqrt{2} }{3}

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C  =  -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = \frac{10\sqrt{2} }{3}

From B = \frac{10\sqrt{2} }{3}

From C = \frac{10\sqrt{2} }{3}

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3 years ago
What is the Radius of a cylindrical water tank that has a circumference of 85 meters?
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C=2pr

r=C/(2p) and we are given C=85 so

r=85/(2p) meters

r≈13.53 meters (to nearest one-hundredth of a meter)
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