Answer:
I think these are the right answers. The answer to one is 32. The answer to two is 38.
1: 2[18-(5+3^2)/7]
2[18-(5+9)/7]
2[18-14/7]
2[18-2]
2 times 16 = 32
2: I used a calculator for this one.
The x- intercept is where y = 0 on the graph and the y- intercept is where x= 0 on the graph. When X=0, all the terms, except for the constant are equal to zero, thus the y- intercept is the constant. y=10 when x=0. Use the quadratic formula to find the x value where y=0.
x= (-b +or- sqrt(b^2 -4ac))/2a
y=ax^2 +bx +c
The answer for the x- int is imaginary. This happens because 10 is the parabola's minimum value and it never touches the x- axis. y-int is 10
Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get
The required equation of the quadratic function is where, a is a constant.
Putting a=1, we get
![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is .
Answer:
D) Only (-1,9) is a solution.
Step-by-step explanation:
x+y =8
x^2 + y = 10
Lets check the first point (-1,9)
Put in x =-1 y =9
x+y =8
-1+9 = 8
8 =8
This works
x^2 + y = 10
(-1)^2 +9 =10
1+9 = 10
10 = 10
This works
Lets check the second point (-2,6)
Put in x =-2 y =6
x+y =8
-2+6 = 8
4=8
This does not work
We can stop now. (-2,6) cannot be a solution
