Answer:
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Step-by-step explanation:
Answer:




Step-by-step explanation:
Given
I will answer this question using the attached triangle
Solving (a): Sine and Cosine A
In trigonometry:
and

So:

Substitute values for BC and BA




Substitute values for AC and BA



Solving (b): Sine and Cosine B
In trigonometry:
and

So:

Substitute values for AC and BA




Substitute values for BC and BA



Using a calculator:

So:

-- approximated

-- approximated

So:

--- approximated

--- approximated
Answer:
B
Step-by-step explanation:
54/6=9 meaning each face has an area of 9.
Meaning each side has an area of 3.
That means the volume is 3*3*3=27
N=1/2MP? Since n would be the midpoint you have to divide the segment into two.
Answer: You determine the coefficient by looking to see if there is a number in front of a variable. If there is a number in front of the variable, then that is the coefficient. The coefficient is the number, and the variable is the letter.
Step-by-step explanation: Hope this helps