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3 years ago

Can someone please help me with this?

Physics

2 answers:

ikadub [295]3 years ago

8 0

Answer:

the answer is A.

Jet001 [13]3 years ago

6 0

Answer:

The Answer Is B.

It's Hard To Explain You Just Have To Trust Me

Explanation:

If It's Correct (Which i am certain that it is) can you plz award me with Brainliest

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3 years ago

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3 years ago

Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!

Ainat [17]

The total electrostatic force on charge A is $28 \mu N$

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

$x_A = 0\\x_B = 10 m\\x_C = 20 m$

The magnitudes of the three charges are:

$q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C$

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

$F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N$

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

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3 years ago

The time it takes for one wavelength to pass a fixed point is known as:

laiz [17]

The time it takes for one wavelength to pass a fixed point is known as PERIOD.

In fact, the period is defined as the time it takes a wave to make one complete oscillation: since the wavelength is the distance between two consecutive points of the wave with same shape, it means that the time it takes for one wavelength to pass a fixed point in space is exactly the period.

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4 years ago