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Dafna1 [17]
3 years ago
13

a ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2 . what is the final velocity of the

ball after 6.0 seconds?
Physics
1 answer:
frozen [14]3 years ago
8 0
Using v=u+at, Where v is final velocity(m/s), u is initial velocity(m/s), a is acceleration(m/s^2) and t is time(s). 

v = 0 + 3.2*6
v=19.2 m/s.
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