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Dmitry [639]
4 years ago
14

Can someone please help meeeeeee

Physics
1 answer:
mart [117]4 years ago
3 0

Answer:1 or 2 option

Explanation:

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Answer:

The speed of the stone is

v = 7.45 m/s

Explanation:

Length, L=0.551m

maximum tension in the spring = 9.6%

So let speed of stone be

Tv = TH + 9.6/ 100 * TH

Tv - m*g = m*v^2/L

TH = m*v^2 / L

Factor mass to cancel in the equation

Solve to v

v^2= L*g*100 / 9.6

Replacing numeric:

v^2=0.551m*9.8m/s^2*100 / 9.6

v = sqrt( 56.24 m^2/s^2)

v = 7.45 m/s  

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The diagram shows a circuit with a 3-cell battery, a light bulb, and four labeled locations. Which statement describes the direc
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B + C D Current is directed from A to B and from D to C to the bulb. Current is directed from A to B to C to D. Current is directed from D to C to B to A.

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Which of the following best explains how budgeting helps consumers reach their financial goals? A)budgets provide consumers with
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3 years ago
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What are the answers
Harman [31]

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3 years ago
The mean diameters of planets A and B are 8.1 × 103 km and 1.4 × 104 km, respectively. The ratio of the mass of planet A to that
lisabon 2012 [21]

Answer:

dA/dB = 4.955

Approximately, the ratio is 5/1

(Where dA is mean density for planet A while dB is mean density for planet B)

Explanation:

Mass of A = mA

Mass of B = mB

mA/mB = 0.96

Mean radius for A = mA = (8.1 × 10^3)/2 = 4.05 × 10^3 km

Mean radius for B = mB = (1.4 × 10^4)/2

= 7×10^3km

Density = mass/volume

Volume of a sphere = 4/3Πr3

Mean volume for A = (4/3) × Π × (4.05 × 10^3)^3

= 2.784 × 10^11 km3

Mean volume for B = 4/3×Π×(7×10^3)^3

= 1.437 × 10^12km3

Since m/v = d ( where m = mass, v = volume and d = density)

mA = 2.784 × 10^11 km3 × dA ...equation 1

mB= 1.437 × 10^12km3 × dB... equation 2

but mA/mB= 0.96

mA = 0.96 × mB

substitute for mA in equation 1

0.96 × mB = 2.784 × 10^11 x dA equation 3

Substitute for mB in equation 3..

(refer to equation 2)

0.96×1.437×10^12 × dB = 2.784 × 10^11 × dA .....equation 4

divide through by the coefficient of dA

dA = (0.96×1.437×10^12×dB)/(2.784 × 10^11)

divide through by dB

dA/dB = 4.955

therefore, the ratio of dA to dB is 5/1

Therefore, the mean density of A is almost five times that of B

7 0
3 years ago
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