To solve this problem we will apply the concepts related to energy conservation. From this conservation we will find the magnitude of the amplitude. Later for the second part, we will need to find the period, from which it will be possible to obtain the speed of the body.
A) Conservation of Energy,
Here,
m = Mass
v = Velocity
k = Spring constant
A = Amplitude
Rearranging to find the Amplitude we have,
Replacing,
(B) For this part we will begin by applying the concept of Period, this in order to find the speed defined in the mass-spring systems.
The Period is defined as
Replacing,
Now the velocity is described as,
We have all the values, then replacing,
The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
- <em>Pressure on the 13 th floor, P₁ = 35 PSI</em>
- <em>Distance between each floor, d = 10 ft</em>
The vertical pressure of the water is calculated as follows;
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
Learn more about vertical height and pressure here: brainly.com/question/15691554
Answer:
440J
Explanation:
First, let us find the <u>weight </u>of the barbell.
The formula to find the weight is :
W = m × g
Here,
m ⇒ mass ⇒ 20 kg
g ⇒ acceleration of gravity
<u>Let us find it now.</u>
W = m × g
W = 20 kg × 10 ms⁻²
W = 200N
And now let us find<u> the work done by this weight lifter.</u>
Work = Force × Displacement
<u>Let us find it now.</u>
Work = Force × Displacement
= 200N × 2.2m
=<u> 440J</u>
25/2=12.5
12.5 N is equal to 1 centimeter
Plug in 12.5 in for whatever the value of the centimeter is
Example
i want to know how many Newtons of force are needed to get 5 cm of extension
12.5*5=62.5
This is all i've got for your question because its not very specific.
Good Luck
Answer:
Yeah, it can be diffracted. Though it depends on a diffracting medium.
It must have some magnetic fields .
Forexample; X-ray diffraction where electrons are diffracted to the target filament.