Marshall took $36.75 to a fair. Each ticket into the fair costs x dollars. Marshall bought 3 tickets. Which

givi [52]

Think this way:

What is biggest number that EVENLY divides into 240 and 432?

5 0

3 years ago

The probability that a certain hockey team will win any given game is 0.3773 based on their 13 year win history of 389 wins out

notsponge [240]

Answer:

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the teams wins, or they do not win. The probability of the team winning a game is independent of any other game, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3773.

This means that $p = 0.3773$

Their schedule for November contains 12 games.

This means that $n = 12$

Find the probability that the hockey team wins at least 3 games in November.

This is:

$P(X \geq 3) = 1 - P(X < 3)$

In which:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3773)^{0}.(0.6227)^{12} = 0.0034$

$P(X = 1) = C_{12,1}.(0.3773)^{1}.(0.6227)^{11} = 0.0247$

$P(X = 2) = C_{12,2}.(0.3773)^{2}.(0.6227)^{10} = 0.0824$

Then

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0034 + 0.0247 + 0.0824 = 0.1105$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1105 = 0.8895$

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

3 0

2 years ago

If f Subscript x(a,b)equals f Subscript y(a,b)equals0, does it follow that f has a local maximum or local minimum at (a,b)?

Anna [14]

Answer:

D.

Step-by-step explanation:

The point must be a critical point but it could be a saddle point. If the point is a saddle point it would not be neither a maximum nor a minimum. So it must be critical but it does not follow directly that it has a local maximum or local minimum.

Therefore D. (a,b) would be a candidate, but is not necessarily a maximum or minimum. It could be a saddle.

5 0

3 years ago

Is (6,3) a solution to this system of equations y=3x - 3 3x - y =3

aleksandr82 [10.1K]

Answer:

It is not a solution

Step-by-step explanation:

Plug the point into the equations and check to see if they are true

y=3x - 3

3 = 3(6) -3

3 = 18-3

3 = 15

False

We do not need to check the other equation since this is false

3 0

2 years ago

ILL MARK BRAINLIST IF ITS RIGHT.

erastovalidia [21]

Answer:

Step-by-step explanation:

The formula you should use is

b = 7 * h

You can try any value to see what happens

Let h = 3

b = 3*7

b = 21

4

3 0

2 years ago