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liubo4ka [24]
3 years ago
11

a paint company ants totest wether a new additive will make thier paint resist fading. Which test would include andan acceptable

control group?
Chemistry
1 answer:
luda_lava [24]3 years ago
6 0
There are a few ways to do this. The best way I can think of is to start out the paint with no additives and have that as a control. You can test that on whatever your painting or do it in a lab with heat lamps and lights if that is a possible option. However you decide to do the testing, after starting with the control test, add different additives and see which ones fades less the original without any additives. This is the best scenario for a simple yet informative test.

Hope that helps!
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a 25.0-ml volume of a sodium hydroxide solution requires 19.6 ml of a 0.189 m hydrochloric acid for neutralization. a 10.0- ml v
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<u>Concentration of NaOH = 0.148 molar, M</u>

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<u></u>

Concentration x Volume  will give the number of moles of solute in that volume.  C*V = moles

Concentration  has a unit of (moles/liter).  When multiplied by the liters of solution used, the result is the number of moles.

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This balanced equation tells us that neutralization of NaOH with HCl requires the same number of moles of each.  We just determined that the  moles of HCl used was 0.00370 moles.  Therefore, the 25.0 ml solution of NaOH had the same number of moles:  0.00370 moles NaOH.

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====

The phosphoric acid problem is handled the same way, but with an added twist.  Phosphoric acid is H3PO4.  We learn the 34.9 ml of the same NaOH solution (0.148M) is needed to neutralize the H3PO4.  But now the acid has three hydrogens that will react.  The balanced equation for this reaction is:

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The moles of NaOH that were used is:

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     (0.00172 moles H3PO4)/(0.010 liters H3PO4)

<u>Concentration of H3PO4 = 0.172 molar, M</u>

 

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