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liubo4ka [24]
4 years ago
11

a paint company ants totest wether a new additive will make thier paint resist fading. Which test would include andan acceptable

control group?
Chemistry
1 answer:
luda_lava [24]4 years ago
6 0
There are a few ways to do this. The best way I can think of is to start out the paint with no additives and have that as a control. You can test that on whatever your painting or do it in a lab with heat lamps and lights if that is a possible option. However you decide to do the testing, after starting with the control test, add different additives and see which ones fades less the original without any additives. This is the best scenario for a simple yet informative test.

Hope that helps!
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A substance that can be separated into two or more substances only by a chemical change is
Yuliya22 [10]
<span>A substance that can be separated into two or more substances only by a chemical change is </span><span>known as a </span><span>heterogeneous</span><span> mixture</span>
5 0
3 years ago
A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.
julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

4 0
4 years ago
Use this reaction: 3NaOH + H3PO4--&gt; Na3PO4 + 3H20
uranmaximum [27]
The balanced reaction would be as follows:

<span>3NaOH + H3PO4 --> Na3PO4 + 3H20

We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:

</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4? 

4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>
8 0
3 years ago
NEED ANSWER ASAP, LL MARK BRAINLIEST FOR WHOEVER ANSWERS!!!
belka [17]

Answer:yes

Explanation:

5 0
4 years ago
What intermolecular forces are present among molecules in dimethyl ether, CH3OCH3?
crimeas [40]

Answer:

London forces only

Explanation:

Dimethyl ether is a nonpolar organic compound. Remember that for nonpolar organic substances, London forces are the primary intermolecular forces present.

Since dimethyl ether is a nonpolar organic compound, then it has London forces as its major intermolecular force. Intermolecular forces hold molecules of a substance together in a given state of matter.

5 0
4 years ago
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