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Andrews [41]
2 years ago
8

A 40.04 g sample of a protein contains 17.16 g of carbon, 3.17 g of hydrogen, 13.71 g of oxygen, and the rest being nitrogen. Th

is 40.04-gram sample is known to be 0.07141 moles. Determine the molecular formula of this protein.
Chemistry
1 answer:
Arturiano [62]2 years ago
8 0

Answer:

ffgghhhhhgffffffcvvvvvvvvvvvvvvvvvv

Explanation:

cccvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

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In which layer of the atmosphere can you find meteors?
asambeis [7]
The answer would be d :)
5 0
2 years ago
One way to determine the degree of saturation of a solid-liquid solution is to drop a crystal of the solute into the solution.
Dafna1 [17]

The answer is D: Saturated.

A saturated solution is one in which the exact maximum amount of solute has been dissolved.  So, new solute will not dissolve in the solution.  In contrast, an unsaturated solution can hold more solute, so if that option were correct, the crystal would have dissolved.

The other two terms are a bit more complicated.  A supersaturated solution is one holding an amount of solute above the sustainable limit.  Because of that, when more solute is added, the solution will immediately adjust, and some solute will come out of solution in a precipitate.  Because the crystal isn't growing, we can eliminate this option.

A concentrated solution is one holding a relatively large amount of solute.  However, you can have concentrated solutions that are saturated and unconcentrated (the word for this is dilute) solutions that aren't saturated.  Therefore, we can say that because the crystal doesn't dissolve, this solution is saturated, but we can't say with certainty that it is concentrated.

Because the first three options are invalid, as described above, while the scenario does describe a saturated solution, D is the correct answer.

7 0
3 years ago
Read 2 more answers
Iron (III) nitrate (Fe(NO3)3) solution reacts with sodium hydroxide (NaOH) solution to form a
sveticcg [70]

Answer:

Fe(NO3)3 + 3 NaOH ===》Fe(OH)3 + 3 NaNO3

7 0
2 years ago
Consider the reaction at 500 ° C 500°C . N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽ − 2 NH 3 ( g ) K c = 0.061 N2(g)+3H2(g)↽−−⇀2NH3(g)Kc=0.06
Sav [38]

Answer:

Q = 0.061 = Kc

Explanation:

Step 1: Data given

Temperature = 500 °C

Kc=0.061

1.14 mol/L  N2

5.52 mol/L H2

3.42 mol/L NH3

Step 2: Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium.  

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium.  

Q = (3.42)² / (1.14 * 5.52³)

Q = 11.6964/191.744

Q = 0.061

Q = Kc the reaction is at equilibrium.  

4 0
3 years ago
Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re
bearhunter [10]

Answer:  28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles

The balanced chemical equuation is:

4Al+3O_2\rightarrow 2Al_2O_3  

According to stoichiometry :

4 moles of Al produce == 2 moles of Al_2O_3

Thus 0.556 moles of Al will produce=\frac{2}{4}\times 0.556=0.278moles  of Al_2O_3

Mass of Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0
2 years ago
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