Answer:
+120/169 or -120/169
Step-by-step explanation:
- let
![cos^{-1}[\frac{5}{13} ] = \alpha](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B13%7D%20%20%5D%20%3D%20%5Calpha)
where, alpha is some angle that satisfies the assumed condition.
- so,
[ taking cos to the other side or applying cos on both sides]
- now, substitute this in the given expression
as sin
= 
[by general trigonometry formula: ![cos^{2}[\beta] +sin^{2}[\beta]=1](https://tex.z-dn.net/?f=cos%5E%7B2%7D%5B%5Cbeta%5D%20%20%2Bsin%5E%7B2%7D%5B%5Cbeta%5D%3D1)
]
so if , we can get sin
from the above formula as + or - 12/13
(because, after taking square root on both sides we keep + or -]
- as, sin
![2\beta = 2*sin[\beta ]*cos[\beta ]](https://tex.z-dn.net/?f=2%5Cbeta%20%20%3D%202%2Asin%5B%5Cbeta%20%5D%2Acos%5B%5Cbeta%20%5D)
[by general trigonometry formula]
- here, now
![sin[2\alpha ]=2*(+or- 12/13)*5/13\\](https://tex.z-dn.net/?f=sin%5B2%5Calpha%20%5D%3D2%2A%28%2Bor-%2012%2F13%29%2A5%2F13%5C%5C)
so, the final value can be 120/169 or -120/169.
Answer:
x = 0.25
Step-by-step explanation:
When logs are added together, they are actually multiplied and then the logs taken of the product.
That sentence is actually correct, but you are going to have to read it a couple of times. You might understand it if I actually just solve the problem.
ln(2x) + ln(2) = 0 Combine the two subjects to make 1 ln.
ln (2)(2x) = 0 Now take the antilog
ln(4x) = 0
antilog ln(4x) = e^0 e^0 = 1
4x = 1 See your last problem.
x = 1/4
Now the question is "What's the answer?" It might be 1/4 but I doubt it. A better choice would be x = 1/4 or x = 0.25
I'd try the last one first.
Answer:
The total amount without tax is $141.57
Step-by-step explanation:
Since the coupon is 10% off, they would only have to pay 90% of what they would before (this is before tax). To find out the total after the coupon you would find 90% of 157.30. (This is the longer but better explainable/showable way)
157.30 / 100 = 1.573 (this is 1%)
1.573 * 90 = 141.57
Therefore the answer is $141.57
Move the decimal to the right 4 places to get 4 x 10^-4 which reads four times ten to the negative fourth power
