Answer:
Option A.
Step-by-step explanation:
The given question is incomplete. Here is the complete question.
P(n) models the price (in dollars) of a pack of n bulbs at a certain store.
When does the price of a pack increase faster ?
n 4 10 12
P(n) 12 25 28
When does the price of a pack increase faster ?
A. Between 4 and 10 bulbs
B. Between 10 and 12 bulbs
C. The price increases at the same rat over both the intervals.
To solve this question we will find the rate of increase in the prices per pack in the given intervals.
From n = 4 to n = 10
Rate of increase in price = 
= 
= 2.166 ≈ $2.17 per pack
From n = 10 to n = 12
Rate of increase in price = 
=
= $1.5 per pack
Therefore, price per pack increases faster between n = 4 and n = 10 as compared to n = 10 to n = 12.
Option A is the answer.
Answer:
Every time a new piece of equipment is added to the system, if ifs not properly optimized within the scope of the entire system, you'll end up with wasted energy and operational inefficiencies
Answer- <em>X=12</em>
Step-by-step explanation:
X + 9/7 = 3 is our equation
Then we are going to do the opposite of dividing 7 from 9 which is multiplying 7 from 9. (on both sides)
It will leave us with - X + 9 = 21
Then we will do the opposite of adding 9 to X which is subtracting 9 from X. (also on both sides) ( whenever you do any adding or subtracting or multiplying or dividing on one side you have to do it on the other for the equation to be true)
Now it will leave us with X = 12
And that's our answer! :>