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makkiz [27]
2 years ago
5

Jolene lost her wallet at the mall. It had $10 in it when she got home her brother felt bad and gave her $5.75. represent this s

ituation with expression involving rational numbers. What is the overall change in the amount of money jolene has?
Mathematics
1 answer:
romanna [79]2 years ago
7 0
The ratio is
10 : 5.75
After simplifying the ratio you are left with

1.74 : 1
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15 decreased by twice a number x in algebriac expression
postnew [5]
2x - 15

15 is decreased that is the key word here which indicates subtraction.

twice a number with given variable x is 2x

subtraction always goes behind so 2x - 15
4 0
3 years ago
Find the 99th term of the arithmetic sequence 2, -3, -8,...
3241004551 [841]

Answer:

the sequence is by -5

therefore the next numbers are

-13,-18,-23,-28

7 0
3 years ago
Of all college degrees awarded in the United States, 50% are bachelor's degrees, 59% are earned by women, and 29% are bachelor's
Natasha2012 [34]

Answer:

  P(W|B) = 0.58

Step-by-step explanation:

The conditional probability formula tells you ...

  P(W | B) = P(W&B) / P(B)

  = 0.29/.050

  = 0.58

7 0
3 years ago
Please help I’ll mark you as brainliest if correct!
Alex73 [517]
6ft and 3 inches is 190.5cm
6 0
2 years ago
In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m
olasank [31]
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}

The probability is 1/57.
4 0
2 years ago
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