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arlik [135]
3 years ago
5

Consider three persons, A, B, and C, who are to be seated in a row of three chairs. Suppose A and B are identical twins. How man

y seating arrangements of these persons can there be If you are a total stranger?
Mathematics
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

2 ways

Step-by-step explanation:

The best way to do this is to fix the position of the stranger and then arrange the two identical twins

The number of ways of knowing where the stranger will seat is 1! ways = 1 way

The number of ways of arranging the two identical twins is 2! ways = 2*1 = 2 ways

The number of sitting arrangements = 1 * 2 = 2 ways

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Which of the following inequality should be graphed with a dashed line? Select all that apply.
AURORKA [14]

Answer:

  B, D

Step-by-step explanation:

Any inequality that does not include the "or equal to" case will be graphed with a dashed line.

<h3>Application</h3>

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2 years ago
Question 1 (1 point)
olga55 [171]

Answer:

1) 2y^{2}+4y-9

2) 18x^{5}y^{4}z

3) 6x^{5}-12x^{4}+9x^{3}

4) 40

5) x^{3}-7x^{2}+3x+36


Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}

4) (4a+5)^{2} is a square of a sum, then, by definition you have:

(a+b)^{2}=a^{2}+2ab+b^{2}

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(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25

The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40

5)  Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36

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3 years ago
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2a+8a
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