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Ivahew [28]
3 years ago
9

Help please practical math

Mathematics
1 answer:
ad-work [718]3 years ago
6 0
Greetings!

The second option would be correct as the sales in January and June were both at $240,000, based of the graph. 

Hope this helps.
-Benjamin
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Zenin earns $142 per shift at his new job. During a pay period, he works 12 shifts. What would his pay be for that period?
Degger [83]

Answer:

total pay for his work is $1704

Step-by-step explanation:

given data

Zenin earns =  $142 per shift

total shifty = 12

to find out

What would his pay for 12  shift

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3 0
3 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

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What is four blank four blank four equals 4
attashe74 [19]
4 - 4 + 4 = 4.
four minus for plus four equals four.
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