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Kruka [31]
3 years ago
14

Explain how you found the gfc of 12a^2 b^6, 28a^4, and 42ab^3

Mathematics
1 answer:
bija089 [108]3 years ago
6 0

Answer: 4a

<u>Step-by-step explanation:</u>

12a²b⁶                         28a⁴                          42ab³

 ∧    ∧                           ∧  ∧                          ∧   ∧

2  6  a² b⁶                    7 4  aaaa                 7 6 a b³

   ∧     ∧                          ∧                              ∧     ∧

  2 3  aa bbbbbb          2 2                           2 3   bbb

12a²b⁶: 2 * 2 * 3 * aa * bbbbbb

28a⁴: 2 * 2 * 7 * aaaa

42ab³: 2 * 2 * 3 * 7 * a * bbb  

What do they have in common? two 2s and one a  

GCF = 2 * 2 * a = 4a          

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