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3 years ago

Please help on these questions ASAP! I will give brainliest

Mathematics

2 answers:

vekshin13 years ago

8 0

What’s that can’t see

Gwar [14]3 years ago

4 0

Answer:

WITH WHAT

Step-by-step explanation:

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(X1+X2/2). (Y1 + Y2/2) what is this equation called. its 16 letters long plz help need for 10th grade semester finals.

Degger [83]

Answer:

midpoint equation

Step-by-step explanation:

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3 years ago

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alukav5142 [94]

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3 years ago

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3 years ago

Write an expression in factored form that is equivalent to the given expression. 1/2x + 4 . can u also tell how you solved it ?

Rufina [12.5K]

2 ways: Easy and hard
Hard=A
Easy=B
A: 1/2x+4 work from there so we do fun stuff with it make something that can be simplified so 1/2x+4 times (2/2)=x+8 now square the whole thing and put the result in a square root thingie (x+8)^2=x^2+16x+64 $\sqrt{x^2+16x+64}$ multiply the whole thing by 4/4 and put $\sqrt{16} [\tex] on top so then 
[tex] \sqrt{x^2+16x+64}$ times $\frac{ \sqrt{16} }{4}$ = $\frac{\sqrt{(16)(x^2+16x+64)}}{4}$ = $\frac{ \sqrt{16x^2+256x+1024} }{4}$ to solve it, factor out the 16 in the square root and then square root 16 to get 4 then it will be (4 times square root of equation)/4=square root of equatio factor square root of equation and square root it and get x+8 divide by 2 to get 1/2x+4

B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve

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2 years ago

Given the parabola below, find the endpoints of the latus rectum. (x-2)^2=-20(y+2)

Shtirlitz [24]

Answer:

The endpoints of the latus rectum are $(12, -7)$ and $(-8, -7)$ .

Step-by-step explanation:

A parabola with vertex at point $C(x, y) = (h,k)$ and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

$(x-h)^{2} = 4\cdot p \cdot (y-k)$ (1)

Where:

$y$ - Independent variable.

$x$ - Dependent variable.

$p$ - Distance from vertex to the focus.

$h$ , $k$ - Coordinates of the vertex.

The coordinates of the focus are represented by:

$F(x,y) = (h, k+p)$ (2)

The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that $h = 2$ , $k = -2$ and $p = -5$ , then the latus rectum is between the following endpoints: