A coin will be tossed 100 times. You get to pick 11 numbers. If the number of heads turns out to equal one of your 11 numbers, y
ou win a dollar.
Which 11 numbers should you pick, and what is your chance (approximately) of winning? Explain.
1 answer:
Answer:
Numbers:
45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55
Chance:
68.27%
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This is what i got X= 17/2 + Y/2
Answer:
Step-by-step explanation:

$48
Here's how I found it ( just in case )
radius = (4*10^2 + 24^2)/8*10 =
(400 + 576)/80=
976/80 = 12.2
diameter = 12.2 x 2 = 24.4
1.) (-18, -20) (18, 16)
m= 1
2.) (-7, 14) (-11, 4)
m= 5/2
3.) (-5, -4) (3, 9)
m= 13/8
4.) (13, -8) (-9, -1)
m= -7/22