Answer:
$ 327.08
Step-by-step explanation:
Let x = width of the container,
Then Length of the container = 2x
Let h = height of the container,
volume of the container can be calculated as length × width × height
= 2x × x × h
= 2x² h
Then we can say Volume =
= 2x² h=10
If we simplify inorder to get h
We have h= 5/x²
Then the area= (2L×h) +(2xh)
Where L is lenght
x= wish
h= height
= 2× 2x × h+ x× h
= 4x× 5/x + 2x × 5/x
Area = 30/x
Now, the area of the base = length × width
But from question, for the base costs $20 per square meter. Material for the sides costs $12 per square meter
Then the cost C(x)= 2x²× 20+30/x ×12
C(x)= 40x²+35/x²
If we differenciate wrt x we have
C(x)= 80-360/x²
If we equate C(x)=0the
80=360/x²
x= 1.651
If substitute to C(x)= 40x²+35/x²
C(x) = 40(1.651)² + 35/(1.651)²
We have cost= 327.08
