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3 years ago

10

What is the sum of -8 and it’s opposite?

1 answer:

musickatia [10]3 years ago

4 0

Answer:

5+-8=0

Step-by-step explanation:

Its really easy, first, it says sum, so that means add it and then it said opposite. The opposite of -8 is 8, so put it all together and its 8+-8=0

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h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

$a=-2,\\ \\b=2,$

so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

6 0

3 years ago

Find the derivative dy, dx for y equals the quotient of the quantity x cubed minus 5 times x and the quantity x squared minus 1.

Elza [17]

Using the quotient rule

dy/dx = (x^-1) * (3x^2 -5 ) - (x^3 - 5x) * 2x
----------------------------------------------
(x^2 - 1)^2

You are correct

7 0

3 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

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4 years ago

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