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Mariulka [41]
3 years ago
9

Please i need this done ASAP!!!!!!!!! Write the following statement in if-then form. "All freshman are required to attend orient

ation."
Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

If you are a freshman, then you are required to attend orientation

Step-by-step explanation:

The if part is  the given part

The then part is what is going to happen

If you are a freshman, then you are required to attend orientation

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6 There were 35 children and 10 adults at a cookout. What is the ratio of children to total people at the cookout?
Grace [21]
7:9 because there are 35 children and 10 adults. Add 35 and 10 you get 35:45 then you simplify the ratio to get 7:9.
6 0
3 years ago
A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio
Klio2033 [76]

Answer:

  • k = 0.032
  • P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

  P(t)=P_0\cdot e^{kt}

We know from the given points that we can write the equation as ...

  P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t

Comparing this to the desired form, we see that ...

  P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693

So, the approximate equation for P is ...

  P(t)=131.836\cdote^{0.032t}

And the parameters of interest are ...

  • k = 0.032
  • P0 = 131.836
4 0
3 years ago
Divide 33 photos into 2 groups so the ratio is 4 to 7
lapo4ka [179]
First you'll need two equations ( you can use any variables you want)
A= photo group 1
B= photo group 2
First equation:
A + B = 33
This is because the total number of photos from both groups is 33
Second equation:
4A = 7B
This is because the ratio is 4:7 so for every four photos in group A there must be 7 photons in group B.
Then take the first equation A + B = 33 and subtract B from both sides. Making the equation A = 33 - B
Then with that equation, substitute it in for equation 2 and it will look like this. 4(33-B) = 7B
Then distribute the 4 to the 33 and the -B making the equation 132 - 4B = 7B
Then add 4B to each side
Making the equation 132 = 11B
Then to get B by itself you must divide each side by 11 making the equation 132/11 = B which simplifies to 12 = B
Then plug in 12 for B in the first equation like this A + 12 = 33
Then subtract 12 on each side of the equation to isolate A so A = 21

So
A = 21
B = 12
4 0
4 years ago
PLEASE HELP ASAP
rusak2 [61]

There's a lot of different approaches to this question, but the easiest one I see is this:

If a chord goes through the center of the circle, it is a diameter. That's 180 degrees we don't have to worry about. 47 is an inscribed angle, so we can multiply it by two to get 94 degrees. Subtract 94 from 180 to get 86.

See y? It's also an inscribed angle. To get it, we just take the 86 we just found for the remaining arc and divide by two.

The measure of y is 43.

5 0
3 years ago
Read 2 more answers
To pass a test 36% marks are needed out of maximum a student gets 123 marks and is declared failed by 39 marks what are maximum
IgorLugansk [536]

If the student got 123 marks and failed by 39, your first step would be to add the two together, getting 162. This is the amount of marks needed to pass the test.

You would then divide 162 by .36 (.36 is equivalent to 36%). This would result in a maximum of 450 marks.

The maximum marks on this test are 450 marks.

8 0
3 years ago
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