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Vladimir [108]
3 years ago
5

Can you break down how to solve the problem ?

Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

A.  y  = \frac{-5x}{2} - 1

Step-by-step explanation:

Given parameters:

Equation of the line:

       5x + 2y = 12

Coordinates = -2, 4

Unknown:

The equation of the line parallel to this line = ?

  • To solve this problem, first, we need to find the slope of the given line.

     Every linear equation have the formula:  y = mx + c

     m is the slope of the line, c is the y- intercept

           5x + 2y = 12

 Express this equation as y = mx + c

                 2y = -5x + 12

                    y = \frac{-5}{2}x  + 6

The slope of this line is \frac{-5}{2}

  • Now, any line that is parallel to another will not cut or cross it at any point. This simply implies they have the same slope.

                  Slope of the line parallel is \frac{-5}{2}

  • Our new line will also take the form y=mx + c,

          Coordinates = -2, 4, x = -2 and y = 4

                     m is \frac{-5}{2}

Now let us solve for C, the y-intercept;

                     4 = - 2 x \frac{-5}{2}  + C

                      4 = 5  + C

                       C = -1

The equation of the line is therefore;

                 y  = \frac{-5x}{2} - 1

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Ganezh [65]

Answer:

  C, E

Step-by-step explanation:

As a rule, these ballistic motion equations are only applicable for heights above the final resting place. Usually, that is the ground (h=0). Time is always measured as a non-negative quantity beginning at the time of launch.

The function is meaningless after the time the object comes to rest on the ground, so the domain of the function extends from 0 until that time.

These considerations allow us to evaluate the offered statements.

  A. The domain never includes negative values. (A is not a true statement)

  B. The heights are the same at times that are symmetrical around the time of the maximum height. Here, that time is about 1.9 seconds, not 1.5 seconds, so the heights will be different at 1 and 2 seconds after launch. (B is not a true statement)

  C. The graph of the function shows the height reaches 0 at about 4.06 seconds, a little after 4 seconds. (C is true)

  D. Based on our answer to C, we know t=10 is outside the domain of the function. (D is not a true statement)

  E. The value of the function is 20 when t=0, so the function tells us the orange is 20 feet above the ground when it is launched. (E is true)

The true statements are C and E.

3 0
2 years ago
Quanto e 45x12 (500-450-550)
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Answer:

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5 0
3 years ago
A walking path across a park is represented by the equation y = -4x+10. A
ad-work [718]

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the algebraic approach would work like this:

-4x + 10 = 1/4x + b

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-4*(4) + 10 = 1/4*(4) + b

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3 0
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Write √3 x √6 in the form b√2 where b is an integer
bagirrra123 [75]

Answer:

3√2

Step-by-step explanation:

√3 x √6

= √3×6

= √18

= √9×2

= √9 × √2

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I hope this was helpful, please rate as brainliest  

7 0
3 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
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