Answer:D. x^2+7
Step-by-step explanation:
If f(x) = 2x² +5 and g(x)=x2-2, find (f-g)(x).A. x^2+3B. 3x^2+3C. 3x^2+7D. x^2+7
There are 12 inches in one foot. 120 x 12 = 1,440 inches. The correct ratio to be placed is the 5th one (aka 12 inches over 1 foot).
Domain is (-10, infinity) and range is negative infinity, positive infinity.
We need to graph this equation:
![16x+2y=300](https://tex.z-dn.net/?f=16x%2B2y%3D300)
Its solutions are the points through which it graph passes. Since it's a linear equation its graph is a straight line and we only need two of its points to draw it. But before graphing let's re-write the equation. We can substract 16x from both sides:
![\begin{gathered} 16x+2y=300 \\ 16x+2y-16x=300-16x \\ 2y=300-16x \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2016x%2B2y%3D300%20%5C%5C%2016x%2B2y-16x%3D300-16x%20%5C%5C%202y%3D300-16x%20%5Cend%7Bgathered%7D)
And we divide both sides by 2:
![\begin{gathered} \frac{2y}{2}=\frac{300-16x}{2}=\frac{300}{2}-\frac{16x}{2} \\ y=150-8x \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B2y%7D%7B2%7D%3D%5Cfrac%7B300-16x%7D%7B2%7D%3D%5Cfrac%7B300%7D%7B2%7D-%5Cfrac%7B16x%7D%7B2%7D%20%5C%5C%20y%3D150-8x%20%5Cend%7Bgathered%7D)
So now with this equation if we pick two random x values we'll get their corresponding y values. This way we'll find two points that are part of the graph which is the line that passes through both. We can begin with x=0:
![y=150-8\cdot0=150](https://tex.z-dn.net/?f=y%3D150-8%5Ccdot0%3D150)
So the first point is (0,150). Then we can take x=10 and we get:
![y=150-8\cdot10=150-80=70](https://tex.z-dn.net/?f=y%3D150-8%5Ccdot10%3D150-80%3D70)
So the second point is (10,70). Then the graph is the line that passes through points (0,150) and (10,70). In order to represent it
Pemdas
parenthasees exponents mult/division additon/subtraction
parethenasees
x-3 and x+5 we can't do anything with so next
5(x-3)=5x-15
2(x+5)=2x+10
5x-15+2=5x-13
(2x+10-9)=2x+1
(5x-13)-3(2x+1)
-3(2x+1)=-6x-3
5x-13-6x-3=-x-16
4(-x-16)=-4x-64
the answer is -4x-64