I am pretty sure b. is right. This is because 87 is not prime
Actual W/ actual height= model W/ model height
55 ft/ actual height= 1.5 in./ 15 in,
actual height=55 ft*15 in./1.5 in= 550 ft
Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
0.765 (100) + .06 (.0765 x 100)
76.5 + .06 (76.5)
76.5 + 4.59 = 81.09 Chris will pay $81.09
3: m= 2, -3
4: x= -1, 5/2
5: x= -1, -3
6: x= 5/2, -4
